x^(1/2)-20x^(1/4)+100=0

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Solution for x^(1/2)-20x^(1/4)+100=0 equation: 


D( x )

x < 0

x < 0

x in <0:+oo)

x^(1/2)-(20*x^(1/4))+100 = 0

x^(1/2)-20*x^(1/4)+100 = 0

t_1 = x^(1/4)

1*t_1^2-20*t_1^1+100 = 0

t_1^2-20*t_1+100 = 0

DELTA = (-20)^2-(1*4*100)

DELTA = 0

t_1 = 20/(1*2)

t_1 = 10 or t_1 = 10

t_1 = 10

x^(1/4)-10 = 0

1*x^(1/4) = 10 // : 1

x^(1/4) = 10

x^(1/4) = 10 // ^ 4

x = 10000

t_1 = 10

x^(1/4)-10 = 0

1*x^(1/4) = 10 // : 1

x^(1/4) = 10

x^(1/4) = 10 // ^ 4

x = 10000

x in { 10000, 10000 }

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